my geometry skilz are rusty but here goes.
b=arc, c=circumference.
b/c = d/360
c = 2(pi)r
360b = 2(pi)dr
180b/pi = dr
ok i can’t finish this, gotta get back to work. i’m sure there’s trig involved.
sin(d/2) = (a/2)/r
..blahblah. albert, you evil sprinkler of kuaci on the ground for vampires to obsessively count (and get distracted)!
mm.. if i am not wrong.. b=2(3.1415)r so therefore if b is given, r=b/6.283
and d=(3.1415)r^2
should be correct.. hehehe
wat ah?
Thanks for making me feel really stupid, Albert.
i’m soooo stupid……
my geometry skilz are rusty but here goes.
b=arc, c=circumference.
b/c = d/360
c = 2(pi)r
360b = 2(pi)dr
180b/pi = dr
ok i can’t finish this, gotta get back to work. i’m sure there’s trig involved.
sin(d/2) = (a/2)/r
..blahblah. albert, you evil sprinkler of kuaci on the ground for vampires to obsessively count (and get distracted)!
[pi]r^2 is area.
okay, dividing the triangle ARR’ along the vertex,
R sin (D/2) = A/2
R = A / (2 sin (d/2))
B/R = 3.124D/180
substitute R from above to get
B = 3.142ADsin(d/2)/360
wait i realised that’s wrong. just do your algebra and switch.